United States presidential election in Georgia, 1948

United States presidential election in Georgia, 1948
Georgia (U.S. state)
November 2, 1948 (1948-11-02)
 
Nominee Harry Truman Strom Thurmond Thomas E. Dewey
Party Democratic Dixiecrat Republican
Home state Missouri South Carolina New York
Running mate Alben Barkley Fielding L. Wright Earl Warren
Electoral vote 12 0 0
Popular vote 254,646 85,055 76,691
Percentage 60.81% 20.31% 18.31%
President before election

Harry Truman
Democratic

 Elected President

Harry Truman
Democratic

The 1948 United States presidential election in Georgia took place throughout the contiguous 48 states. Voters chose 12 representatives, or electors, to the Electoral College, who voted for President and Vice President.

On Election Day, President Harry Truman won Georgia in a landslide. He carried the state by 40.5% over his nearest competitor, Strom Thurmond of the Dixiecrat party.

Results

United States presidential election in Georgia, 1948 [1]
Party Candidate Votes Percentage Electoral votes
Democratic Harry Truman 254,646 60.81% 12
Dixiecrat Strom Thurmond 85,055 20.31% 0
Republican Thomas E. Dewey 76,691 18.31% 0
Progressive Henry Wallace 1,636 0.39% 0
Prohibition Claude Watson 732 0.17% 0
Socialist (Write-in) Norman Thomas 3 0.01% 0

References

  1. ↑ http://uselectionatlas.org/RESULTS/
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