United States presidential election in New Mexico, 1992

United States presidential election in New Mexico, 1992

November 3, 1992

Nominee Bill Clinton George H.W. Bush Ross Perot Party Democratic Republican Independent Home state Arkansas Texas Texas Running mate Al Gore Dan Quayle James Stockdale Electoral vote 5 0 0 Popular vote 261,617 212,824 91,895 Percentage 45.9% 37.3% 16.1%

County Results   Clinton—60-70%   Clinton—50-60%   Clinton—40-50%   Bush—40-50%   Bush—50-60%

President before election George H. W. Bush Republican Elected President Bill Clinton Democratic

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The 1992 United States presidential election in New Mexico took place on November 3, 1992, as part of the 1992 United States presidential election. This was the 20th U.S. Presidential election that New Mexico participated in since 1912. New Mexico voters chose five electors to the Electoral College, who voted for President and Vice President.

New Mexico was won by Governor Bill Clinton (D-Arkansas) with 45.90% of the popular vote over incumbent President George H.W. Bush (R-Texas) with 37.34%. Businessman Ross Perot (I-Texas) finished in third with 16.12% of the popular vote.^[1] Clinton ultimately won the national vote, defeating incumbent President Bush.^[2]

Results

References

State results of the 1992 U.S. presidential election
Candidates	Bill Clinton George H. W. Bush Ross Perot Lyndon LaRouche Full list
General articles	Election timeline Democratic primaries Republican primaries Republican Convention Democratic Convention Debates
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Other 1992 elections	House Senate Gubernatorial