Douglas Township, Saunders County, Nebraska

Douglas Township
Township

Location in Saunders County
Coordinates: 41°21′06″N 096°44′13″W / 41.35167°N 96.73694°W / 41.35167; -96.73694Coordinates: 41°21′06″N 096°44′13″W / 41.35167°N 96.73694°W / 41.35167; -96.73694
Country United States
State Nebraska
County Saunders
Area
  Total 32.01 sq mi (82.91 km2)
  Land 32.01 sq mi (82.91 km2)
  Water 0 sq mi (0 km2)  0%
Elevation 1,309 ft (399 m)
Population (2000)
  Total 196
  Density 6.1/sq mi (2.4/km2)
GNIS feature ID 0837967

Douglas Township is one of twenty-four townships in Saunders County, Nebraska, United States. The population was 196 at the 2000 census. A 2006 estimate placed the township's population at 205.[1]

See also

References

  1. "Subcounty population estimates: Nebraska 2000-2006" (CSV). United States Census Bureau, Population Division. 2007-06-28. Retrieved 2008-03-04.

External links


This article is issued from Wikipedia - version of the 11/16/2013. The text is available under the Creative Commons Attribution/Share Alike but additional terms may apply for the media files.