United States presidential election in Idaho, 1996

United States presidential election in Idaho, 1996
Idaho
November 5, 1996

 
Nominee Bob Dole Bill Clinton Ross Perot
Party Republican Democratic Reform
Home state Kansas Arkansas Texas
Running mate Jack Kemp Al Gore Patrick Choate
Electoral vote 4 0 0
Popular vote 256,595 165,443 62,518
Percentage 52.2% 33.7% 12.7%

County Results
  Clinton—60-70%
  Clinton—50-60%
  Clinton—40-50%
  Dole—40-50%
  Dole—50-60%
  Dole—60-70%
  Dole—70-80%

President before election

Bill Clinton
Democratic

Elected President

Bill Clinton
Democratic

The 1996 United States presidential election in Idaho took place on November 5, 1996 as part of the 1996 United States presidential election. Voters chose 4 representatives, or electors to the Electoral College, who voted for President and Vice President.

Idaho was won by Senator Bob Dole (R-KS) over President Bill Clinton (D), with Dole winning 52.18% to 33.65% by a margin of 18.53%. Billionaire businessman Ross Perot (Reform Party of the United States of America-TX) finished in third with 12.71% of the popular vote .[1]

Results

United States presidential election in Idaho, 1996
Party Candidate Running mate Votes Percentage Electoral votes
Republican Bob Dole Jack Kemp 256,595 52.18% 4
Democratic Bill Clinton (incumbent) Al Gore 165,443 33.65% 0
Reform Ross Perot Patrick Choate 62,518 12.71% 0
Libertarian Harry Browne Jo Jorgensen 3,325 0.68% 0
U.S. Taxpayers' Party Howard Phillips Herbert Titus 2,230 0.45% 0
Natural Law Dr. John Hagelin Dr. V. Tompkins 1,600 0.33% 0
Write-in Charles Collins Rosemary Giumarra 7 0.00% 0
Other write-in 1 0.00% 0
Totals 491,719 100.0% 4

References

Precinct Election Results from Idaho Secretary of State http://www.sos.idaho.gov/elect/results.htm

See also

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