Sherman Township, Hardin County, Iowa
| Sherman Township | |
|---|---|
| Township | |
| Coordinates: 42°20′23″N 093°24′17″W / 42.33972°N 93.40472°WCoordinates: 42°20′23″N 093°24′17″W / 42.33972°N 93.40472°W | |
| Country |
 United States |
| State |
 Iowa |
| County | Hardin |
| Area | |
| • Total | 35.98 sq mi (93.19 km2) |
| • Land | 35.98 sq mi (93.19 km2) |
| • Water | (0%) 0 sq mi ((0%) 0 km2) |
| Elevation[1] | 1,142 ft (348 m) |
| Population (2000) | |
| • Total | 461 |
| • Density | 13.2/sq mi (5.1/km2) |
| FIPS code | 468 697[2][3] |
| GNIS feature ID | 0468696 |
Sherman Township is a township located in Hardin County, Iowa. As of the 2010 Census, its population was 738.[4][1]
History
Sherman Township was founded in 1870.[5] It is named for William Tecumseh Sherman.[6]
References
- 1 2 "US Board on Geographic Names". United States Geological Survey. 2007-10-25. Retrieved 2008-01-31.
- ↑ "American FactFinder". United States Census Bureau. Retrieved 2008-01-31.
- ↑ U.S. Geological Survey Geographic Names Information System: Sherman Township, Hardin County, Iowa
- ↑ "Find a County". National Association of Counties. Retrieved 2011-06-07.
- ↑ Moir, William J. (1911). Past and Present of Hardin County, Iowa. Unigraphic. p. 319.
- ↑ History of Hardin County, Iowa. Union Publishing Company. 1883. p. 904.
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