Sand Creek Township, Jennings County, Indiana

Sand Creek Township
Township

Location in Jennings County
Coordinates: 39°05′16″N 85°36′25″W / 39.08778°N 85.60694°W / 39.08778; -85.60694Coordinates: 39°05′16″N 85°36′25″W / 39.08778°N 85.60694°W / 39.08778; -85.60694
Country United States
State Indiana
County Jennings
Government
  Type Indiana township
Area
  Total 27.95 sq mi (72.4 km2)
  Land 27.72 sq mi (71.8 km2)
  Water 0.23 sq mi (0.6 km2)  0.82%
Elevation 725 ft (221 m)
Population (2010)
  Total 872
  Density 31.5/sq mi (12.2/km2)
GNIS feature ID 0453833

Sand Creek Township is one of eleven townships in Jennings County, Indiana, United States. As of the 2010 census, its population was 872 and it contained 365 housing units.[1]

Geography

According to the 2010 census, the township has a total area of 27.95 square miles (72.4 km2), of which 27.72 square miles (71.8 km2) (or 99.18%) is land and 0.23 square miles (0.60 km2) (or 0.82%) is water.[1] The streams of Bear Creek, Fish Creek, Ice Creek, Millstone Creek, Poplar Root Creek and Rock Creek run through this township.

Unincorporated towns

Adjacent townships

Cemeteries

The township contains three cemeteries: Bear Creek, Day and Fish Creek.

Major highways

References

  1. 1 2 "Population, Housing Units, Area, and Density: 2010 - County -- County Subdivision and Place -- 2010 Census Summary File 1". United States Census. Retrieved 2013-05-10.
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