Position operator

In quantum mechanics, the position operator is the operator that corresponds to the position observable of a particle. The eigenvalue of the operator is the position vector of the particle.^[1]

Introduction

In one dimension, the square modulus of the wave function, $|\psi |^{2}=\psi ^{*}\psi$ , represents the probability density of finding the particle at position $x$ . Hence the expected value of a measurement of the position of the particle is

\langle x \rangle = \int_{-\infty}^{+\infty} x |\psi|^2 dx = \int_{-\infty}^{+\infty} \psi^* x \psi dx

Accordingly, the quantum mechanical operator corresponding to position is ${\hat {x}}$ , where

\hat{x} \psi(x) = x\psi(x)

The circumflex over the x on the left side indicates an operator, so that this equation may be read The result of the operator x acting on any function ψ(x) equals x multiplied by ψ(x). Or more simply, the operator x multiplies any function ψ(x) by x.

Eigenstates

The eigenfunctions of the position operator, represented in position space, are Dirac delta functions. To show this, suppose that $\psi$ is an eigenstate of the position operator with eigenvalue $x_{0}$ . We write the eigenvalue equation in position coordinates,

\hat{x}\psi(x) = x \psi(x) = x_0 \psi(x)

recalling that ${\hat {x}}$ simply multiplies the function by $x$ in the position representation. Since $x$ is a variable while $x_{0}$ is a constant, $\psi$ must be zero everywhere except at $x = x_0$ . The normalized solution to this is

\psi(x) = \delta(x - x_0)

Although such a state is physically unrealizable and, strictly speaking, not a function, it can be thought of as an "ideal state" whose position is known exactly (any measurement of the position always returns the eigenvalue $x_{0}$ ). Hence, by the uncertainty principle, nothing is known about the momentum of such a state.

Three dimensions

The generalisation to three dimensions is straightforward. The wavefunction is now $\psi(\bold{r},t)$ and the expectation value of the position is

\langle \bold{r} \rangle = \int \bold{r} |\psi|^2 d^3 \bold{r}

where the integral is taken over all space. The position operator is

\bold{\hat{r}}\psi=\bold{r}\psi

Momentum space

In momentum space, the position operator in one dimension is

{\hat {x}}=i\hbar {\frac {d}{dp}}=i{\frac {d}{dk_{x}}}

Formalism

Consider, for example, the case of a spinless particle moving in one spatial dimension (i.e. in a line). The state space for such a particle is L²(R), the Hilbert space of complex-valued and square-integrable (with respect to the Lebesgue measure) functions on the real line. The position operator, Q, is then defined by:^[2]^[3]

Q (\psi)(x) = x \psi (x)

with domain

D(Q) = \{ \psi \in L^2({\mathbf R}) \,|\, Q \psi \in L^2({\mathbf R}) \}.

Since all continuous functions with compact support lie in D(Q), Q is densely defined. Q, being simply multiplication by x, is a self adjoint operator, thus satisfying the requirement of a quantum mechanical observable. Immediately from the definition we can deduce that the spectrum consists of the entire real line and that Q has purely continuous spectrum, therefore no discrete eigenvalues. The three-dimensional case is defined analogously. We shall keep the one-dimensional assumption in the following discussion.

Measurement

As with any quantum mechanical observable, in order to discuss measurement, we need to calculate the spectral resolution of Q:

Q = \int \lambda d \Omega_Q(\lambda).

Since Q is just multiplication by x, its spectral resolution is simple. For a Borel subset B of the real line, let $\chi _B$ denote the indicator function of B. We see that the projection-valued measure Ω_Q is given by

\Omega_Q(B) \psi = \chi _B \psi ,

i.e. Ω_Q is multiplication by the indicator function of B. Therefore, if the system is prepared in state ψ, then the probability of the measured position of the particle being in a Borel set B is

|\Omega_Q(B) \psi |^2 = | \chi _B \psi |^2 = \int _B |\psi|^2 d \mu ,

where μ is the Lebesgue measure. After the measurement, the wave function collapses to either

$\frac{\Omega_Q(B) \psi}{ \|\Omega_Q(B) \psi \|}$

$\frac{(1-\chi _B) \psi}{ \|(1-\chi _B) \psi \|}$ , where $\| \cdots \|$ is the Hilbert space norm on L²(R).

References

↑ Atkins, P.W. (1974). Quanta: A handbook of concepts. Oxford University Press. ISBN 0-19-855493-1.
↑ McMahon, D. (2006). Quantum Mechanics Demystified (2nd ed.). Mc Graw Hill. ISBN 0 07 145546 9.
↑ Peleg, Y.; Pnini, R.; Zaarur, E.; Hecht, E. (2010). Quantum Mechanics (2nd ed.). McGraw Hill. ISBN 978-0071623582.

Operators in physics

General

Space and time	Parity Time evolution D'Alembert operator

Particles	C-symmetry

Operators for operators	Ladder operator Anti-symmetric operator

Quantum

Fundamental	Position Momentum Rotation

Energy	Total energy Kinetic energy Hamiltonian

Angular momentum	Spin Orbital Total

Electromagnetism	Transition dipole moment

Optics	Displacement Squeeze Quantum correlator Hanbury Brown and Twiss effect

Particle physics	Creation and annihilation Casimir invariant

This article is issued from Wikipedia - version of the 8/17/2016. The text is available under the Creative Commons Attribution/Share Alike but additional terms may apply for the media files.