Greenbriar, Florida

Greenbriar, Florida
Census-designated place & Unincorporated community
Greenbriar, Florida
Coordinates: 28°0′40″N 82°45′9″W / 28.01111°N 82.75250°W / 28.01111; -82.75250Coordinates: 28°0′40″N 82°45′9″W / 28.01111°N 82.75250°W / 28.01111; -82.75250
Country  United States
State  Florida
County  Pinellas
Area
  Total 0.6 sq mi (1.6 km2)
  Land 0.6 sq mi (1.5 km2)
  Water 0.04 sq mi (0.1 km2)
Elevation 55 ft (17 m)
Population (2010)
  Total 2,502
  Density 4,100/sq mi (1,600/km2)
Time zone Eastern (EST) (UTC-5)
  Summer (DST) EDT (UTC-4)
Area code(s) 813

Greenbriar is an unincorporated community and census-designated place (CDP) in Pinellas County, Florida, United States. The population was 2,502 at the 2010 census.[1]

Geography

Greenbriar is located at 28°0′40″N 82°45′9″W / 28.01111°N 82.75250°W / 28.01111; -82.75250 (28.0113, -82.7527).[2] It is bordered by the city of Dunedin to the north and west, the city of Clearwater to the east, and by unincorporated Pinellas County land to the south.

According to the United States Census Bureau, the CDP has a total area of 0.62 square miles (1.6 km2), of which 0.58 square miles (1.5 km2) is land and 0.04 square miles (0.1 km2) (5.82%) is water.[2]

References

This article is issued from Wikipedia - version of the 4/20/2016. The text is available under the Creative Commons Attribution/Share Alike but additional terms may apply for the media files.